I met a problem on opencart 2.0.1.1, I can not edit the orders in backend.
Every time the same error:
SyntaxError Unexpected end of input OK
I already did all these things:
1. In Opencart Admin, go to Settings >> API and create a new user.
2. In cPanel navigate to phpMyAdmin and then select your database where your store is installed.
3. Find table oc_setting and then find key "config_api_id".
4. Set the value field to 1 where key = config_ap_id (it was set to 0 on my system).
5. Next go to table oc_api and check that api_id = 1
Problem still not resolve, I found many many solution, but all not work for me.
I think maybe this is a bug for the software.
I hope somebody can help me.
Is your site in maintainence mode? You should turn it off.
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I looked all over the internet and found no answer.
Basically my problem is whenever I try to edit orders and change stores I get the SyntaxError: JSON.parse: unexpected end of data at line 1 column 1 of the JSON data OK in firefox and in chrome I get SyntaxError: Unexpected end of input OK.
Has anyone found a "real" solution for this because I tried all that was suggested but they don't work. From changing the api_id to making a secondary API. And even the .htaccess method.
Basically my problem is whenever I try to edit orders and change stores I get the SyntaxError: JSON.parse: unexpected end of data at line 1 column 1 of the JSON data OK in firefox and in chrome I get SyntaxError: Unexpected end of input OK.
Has anyone found a "real" solution for this because I tried all that was suggested but they don't work. From changing the api_id to making a secondary API. And even the .htaccess method.
I have exactly the same problem.
When I try to edit an order in admin panel, I get the following error:
On Google Chrome display:
"SyntaxError Unexpected end of input OK"
On Firefox display:
"SyntaxError: Json.parse: unexpected end of data at line 1 column 1 of the JSON Data OK"
Things that I tried:
A)
1. In Opencart Admin, go to Settings >> API and create a new user.
2. In cPanel navigate to phpMyAdmin and then select your database where your store is installed.
3. Find table oc_setting and then find key "config_api_id".
4. Set the value field to 1 where key = config_ap_id
5. Next go to table oc_api and check that api_id = 1
In my database it was set correctly to "1"
B) My site is NOT in maintenance mode.
C) mod_security is OFF
D) file htaccess is disabled. It named htaccess.txt, as it a new fresh installation of opencart 2.0.1.1
Any other ideas?
When I try to edit an order in admin panel, I get the following error:
On Google Chrome display:
"SyntaxError Unexpected end of input OK"
On Firefox display:
"SyntaxError: Json.parse: unexpected end of data at line 1 column 1 of the JSON Data OK"
Things that I tried:
A)
1. In Opencart Admin, go to Settings >> API and create a new user.
2. In cPanel navigate to phpMyAdmin and then select your database where your store is installed.
3. Find table oc_setting and then find key "config_api_id".
4. Set the value field to 1 where key = config_ap_id
5. Next go to table oc_api and check that api_id = 1
In my database it was set correctly to "1"
B) My site is NOT in maintenance mode.
C) mod_security is OFF
D) file htaccess is disabled. It named htaccess.txt, as it a new fresh installation of opencart 2.0.1.1
Any other ideas?
Last edited by rlasmar on Thu Mar 12, 2015 7:21 am, edited 2 times in total.
First: Why this is in Bugs thread?chilledworld wrote:I have the same problem, I cannot edit any orders and I cannot change the order status.
You see in admin setting/setting > edit > tab option > API user.
Is it enabled?
I have tried all these things but nothing works
A)
1. In Opencart Admin, go to Settings >> API and create a new user.
2. In cPanel navigate to phpMyAdmin and then select your database where your store is installed.
3. Find table oc_setting and then find key "config_api_id".
4. Set the value field to 1 where key = config_ap_id
5. Next go to table oc_api and check that api_id = 1
In my database it was set correctly to "1"
B) My site is NOT in maintenance mode.
C) mod_security is OFF
D) file htaccess is disabled. It named htaccess.txt, as it a new fresh installation of opencart 2.0.1.1
Mod_security is not enabled but suhosin
A)
1. In Opencart Admin, go to Settings >> API and create a new user.
2. In cPanel navigate to phpMyAdmin and then select your database where your store is installed.
3. Find table oc_setting and then find key "config_api_id".
4. Set the value field to 1 where key = config_ap_id
5. Next go to table oc_api and check that api_id = 1
In my database it was set correctly to "1"
B) My site is NOT in maintenance mode.
C) mod_security is OFF
D) file htaccess is disabled. It named htaccess.txt, as it a new fresh installation of opencart 2.0.1.1
Mod_security is not enabled but suhosin
If this is not work (even if all the settings are correct) error is your server. you may ask in web hosting, is it php cURL Library in Use?bleekk wrote:I have tried all these things but nothing works
A)
1. In Opencart Admin, go to Settings >> API and create a new user.
2. In cPanel navigate to phpMyAdmin and then select your database where your store is installed.
3. Find table oc_setting and then find key "config_api_id".
4. Set the value field to 1 where key = config_ap_id
5. Next go to table oc_api and check that api_id = 1
In my database it was set correctly to "1"
B) My site is NOT in maintenance mode.
C) mod_security is OFF
D) file htaccess is disabled. It named htaccess.txt, as it a new fresh installation of opencart 2.0.1.1
Mod_security is not enabled but suhosin
Do you mean that the session 'cookie' is found?rlasmar wrote:I have tested all possible solutions in this topic and don't work.
The cURL is activated.
http://forum.opencart.com/viewtopic.php ... pi#p531625
Quite funny ...
Step 2 of the installer shows everyone the result of the magic_quotes setting.
Red = ON, Green = OFF (should be green!).
What for do you think is this?
Just for fun .. ?
Step 2 of the installer shows everyone the result of the magic_quotes setting.
Red = ON, Green = OFF (should be green!).
What for do you think is this?
Just for fun .. ?
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